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x^2-2514.18x+7551.54=0
a = 1; b = -2514.18; c = +7551.54;
Δ = b2-4ac
Δ = -2514.182-4·1·7551.54
Δ = 6290894.9124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2514.18)-\sqrt{6290894.9124}}{2*1}=\frac{2514.18-\sqrt{6290894.9124}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2514.18)+\sqrt{6290894.9124}}{2*1}=\frac{2514.18+\sqrt{6290894.9124}}{2} $
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